ÖØÐÍÁù½ÇÍø£¬Ò²³ÆÎª¹ÒÍø¡¢À¹Ê¯ÍøLOLs10¾º²Â¹ÙÍø¡¢É½Ìå·À»¤ÍøµÈ¡£
ÖØÐÍÁù½ÇÍøÓÃÓÅÖʸÖË¿»úÆ÷Å¡±à¶ø³ÉË«½Ê¸ñÁù±ßÐνðÊôÍøLOLs10¾º²Â¹ÙÍøLOLs10¾º²Â¹ÙÍø¡£ÖØÐÍÁù½ÇÍøÓÃ;¹ã·º£º¿ÉÓÃÓ򱧮ÂÖ§»¤¡¢É½ÌåÑÒÃæ¹ÒÍøÅ罬¡¢±ßÆÂÖÖÖ²ÂÌ»¯¡¢Ìú·¸ßËÙ¹«Â·¸ôÀ뻤À¸ÍøLOLs10¾º²Â¹ÙÍø£¬Ëü»¹ÄÜÖÆ³ÉʯÁý(ÍøÏä)LOLs10¾º²Â¹ÙÍø¡¢Ê¯µæ(ÍøÏä)LOLs10¾º²Â¹ÙÍø£¬ÓÃÓÚ½ºÓ¡¢µÌ°Ó¼°º£ÌÁµÄ·ÀÖγåË¢ÒÔ¼°ºÓÁ÷½ØÁ÷ÓÃÂÒÊ¯ÍøÏä¡£

Éè¼ÆÉϲ»½ö¿¼ÂÇÁËÒ×ÓÚ°²×°£¬Í¬Ê±»¹¿¼ÂÇÁËÔÚÏñÐüÑÂÕâÑùµÄ¶ñÁÓµØÐÎÌõ¼þÏÂÄÜʵÏÖÕâÖÖ°²×°£¬¼´ÓÃ×îÉÙÁ¿µÄê¹ÌºÍ×îÉÙÁ¿µÄ¿ªÍÚÀ´ÊµÏÖ×î¿ìËÙ¼ò±ãµÄÊ©¹¤°²×°¡£»ùÓÚ·À»¤ÍøË«½Ê½á¹¹µÄÌØÐÔ£¬¼´Ê¹ÔÚ¸ÖË¿ÆÆËðµÄÇé¿öÏÂÒ²Äܹ»³ÐÊÜÂäʯµÄ³å»÷¡£

Áù½ÇÍøÊ¯ÁýÍøÓŵã:
(1)ʹÓ÷½±ã£¬Ö»Ðè½«ÍøÃæÆ½ÆÌµÄÇ½Ãæ¡¢½¨ÖþË®ÄàÖм´¿ÉʹÓÃ;
(2)Ê©¹¤¼ò±ã£¬²»ÐèÌØÊâ¼¼Êõ;
(3)ÓкÜÇ¿µÄµÖÓù×ÔÈ»ÆÆ»µ¼°Ä͸¯Ê´ºÍ¿¹¶ñÁÓÆøºòÓ°ÏìµÄÄÜÁ¦;
(4)¿ÉÒÔ³ÐÊÜ´ó·¶Î§µÄ±äÐÎLOLs10¾º²Â¹ÙÍø£¬¶øÈÔ²»Ì®ËúLOLs10¾º²Â¹ÙÍø¡£Æð¹Ì¶¨±£Î¸ôÈÈ×÷Óà ;
(5) ÓÅÁ¼µÄ¹¤ÒÕ»ù´¡±£Ö¤Á˶Ʋãºñ¶ÈµÄ¾ùÔÈÐÔLOLs10¾º²Â¹ÙÍø£¬¿¹¸¯Ê´ÐÔ¸üÇ¿;
(6)½ÚÔ¼ÔËÊä·ÑÓ᣿ɽ«ÆäËõ³ÉС¾í£¬²¢¾íÈë·À³±Ö½°ü×°£¬Õ¼ÓÿռäºÜÉÙLOLs10¾º²Â¹ÙÍø¡£
(7)ÖØÐÍÁù½ÇÍøÊDzÉÓÃÓÅÖʵÍ̼¸ÖË¿¶ÆÐ¿´óË¿ºÅ±àÖ¯£¬¸ÖË¿µÄ¿¹ÀÇ¿¶È²»ÉÙÓÚ38kg/m2£¬¸ÖË¿µÄÖ±¾¶¿É´ï 2.0mmLOLs10¾º²Â¹ÙÍø¡£